College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 21

Answer

$x\approx32.9501

Work Step by Step

Given expression $.05(1.15)^x=5$ Divide both sides by 0.05. $(1.15)^x=100$ Take log of both sides. $\log(1.15)^x=\log100$ Use the Power Rule of logarithms. $x\log1.15=\log100$ Solve for $x$. $x=\frac{\log100}{\log1.15}$ $x\approx32.9501$
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