## College Algebra (11th Edition)

Using the Product Rule of Logarithms, which is given by $\log_b (xy)=\log_bx+\log_by,$ the given expression, $\log387+\log23 ,$ is equivalent \begin{array}{l}\require{cancel} \log(387\times23) .\end{array} Hence, the answers for Exercise 23 and Exercise 19 are the same.