Answer
$\approx-2.2596$
Work Step by Step
Using $\log_b a=\dfrac{\log a}{\log b}$ or the Change-of-Base Formula and the laws of logarithms, the given expression, $
\log 0.0055
,$ evaluates to
\begin{array}{l}\require{cancel}
\dfrac{\log 0.0055}{\log 10}
\\\\\approx
\dfrac{-2.2596}{1}
\\\\
\approx-2.2596
.\end{array}