## College Algebra (11th Edition)

$7$
$\bf{\text{Solution Outline:}}$ Use the properties of logarithms to simplify the given expression, $\log 10^{7} .$ $\bf{\text{Solution Details:}}$ Using the Power Rule of Logarithms, which is given by $\log_b x^y=y\log_bx,$ the expression above is equivalent \begin{array}{l}\require{cancel} 7\log 10 .\end{array} Since $\log_b b=1,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 7\log_{10} 10 \\\\= 7(1) \\\\= 7 .\end{array}