## College Algebra (11th Edition)

$x=25$
Since $y=b^x$ is equivalent to $\log_b y=x,$ then the given equation, $\log_x 5=\dfrac{1}{2} ,$ is equivalent to \begin{array}{l}\require{cancel} x^{\frac{1}{2}}=5 .\end{array} Squaring both sides, then, \begin{array}{l}\require{cancel} x=25 .\end{array}