## College Algebra (11th Edition)

$x=2$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $3x=7^{\log_7 6} ,$ use the properties of logarithms to find an equivalent expression for the logarithmic expression. Then use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using a property of logarithms which is given by $b^{\log_b x}=x,$ the equation above is equivalent to \begin{array}{l}\require{cancel} 3x=6 .\end{array} Using the properties of equality to isolate the variable results to \begin{array}{l}\require{cancel} x=\dfrac{6}{3} \\\\ x=2 .\end{array}