#### Answer

$\log_{27} 81=\dfrac{4}{3}$

#### Work Step by Step

Since $y=b^x$ is equivalent to $\log_b y=x,$ then the given equation, $
27^{4/3}=81
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{27} 81=\dfrac{4}{3}
.\end{array}

Published by
Pearson

ISBN 10:
0321671791

ISBN 13:
978-0-32167-179-0

$\log_{27} 81=\dfrac{4}{3}$

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