College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 423: 28

Answer

$\frac{1}{2}$

Work Step by Step

Re-write $\sqrt[4]{25}=25^{\frac{1}{4}}$. $x=\log_5{25}^{\frac{1}{4}}$ Write expression in exponential form. $5^x=25^{\frac{1}{4}}$ Re-write both sides in terms of the same base. $5^x=(5^2)^{\frac{1}{4}}$ Set exponents equal. (If $x^a=x^b$, then $a=b$.) $x=2(\frac{1}{4})=\frac{1}{2}$
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