## College Algebra (11th Edition)

$\frac{1}{5}$
Rewrite the equation in exponent format using the definition of logarithm. $7^x=\sqrt[5]{7}$ Rewrite $\sqrt[5]{7}$ and $7^{\frac{1}{5}}$ to get two bases that are the same. $7^x=7^\frac{1}{5}$ If $a^b=a^c$, then $b=c$. Therefore, $x=\frac{1}{5}$. $x=\frac{1}{5}$