College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 423: 21

Answer

$9$

Work Step by Step

$x=2^{\log_2{9}}$ By the Theorem of Inverses, $x=a^{\log_a{x}}$ $\therefore x=9$
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