College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 3 - Section 3.6 - Variation - 3.6 Exercises - Page 366: 23

Answer

$R=850 \text{ ohms}$

Work Step by Step

As resistance $R$ and temperature $T$ vary directly so $R=kT$ (where $k$ is a constant of proportionality) We plug in the known values to obtain: $646\text{ ohms}=k(190K)$ $\implies k=\frac{646\text{ ohms}}{190K}=3.4\frac{ohms}{K}$ Thus, $R=\left(3.4\frac{\text{ ohms}}{K}\right)T$ Now we can find the resistance for $T=250K$ as $R=3.4\frac{\text{ ohms}}{K}(2500K) \\R=850 \text{ ohms}$
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