College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 3 - Section 3.6 - Variation - 3.6 Exercises - Page 366: 22

Answer

$P=75\text{ psi}$

Work Step by Step

As we know that pressure $P$ and depth $h$ are directly proportional so $P=kh$ (where k is constant of proportionality) We plug in the known values to obtain: $50\text{ psi}=k(10\text{ ft})$ $\implies k=\frac{50\text{ psi}}{10\text{ ft}}=5\frac{\text{ psi}}{\text{ft}}$ Thus, $P=\left(5\frac{\text{ psi}}{\text{ ft}}\right)h$ Now we can find the pressure for a depth h=15ft as follows $P=\left(5\frac{\text{ psi}}{\text{ ft}}\right)(15ft)=75\text{ psi}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.