College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Functions - 2.4 Exercises - Page 215: 86

Answer

$7.5$

Work Step by Step

To find the midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ We know that the midpoint between points $(4,6)$ and $(5,9)$ would be: midpoint=$(\displaystyle \frac{4+5}{2},\frac{6+9}{2})$ $=(\frac{9}{2},\frac{15}{2})$ $=(4.5,7.5)$ Thus the $y$ value that corresponds to an $x$ value of $4.5$ is $7.5$.
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