College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Functions - 2.4 Exercises - Page 215: 78

Answer

$slope=3$

Work Step by Step

We calculate the slope between the 2nd and 3rd points, $(1,-3)$ and $(2,0)$: $slope=m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-3)}{2-1}=\frac{3}{1}=3$
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