College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Functions - 2.4 Exercises - Page 215: 82



Work Step by Step

We find the distance between the first and fourth points, $(0,-6)$ and $(3,3)$ by using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2)}$ $d=\sqrt{(3-0)^{2}+(3-(-6))^{2}}$ $=\sqrt{3^{2}+9^{2}}$ $=\sqrt{9+81}$ $=\sqrt{90}$ $=\sqrt{9*10}$ $=3\sqrt{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.