## College Algebra (11th Edition)

$m=\dfrac{1}{5}$
$\bf{\text{Solution Outline:}}$ Convert the given equation, $x-5y=0 ,$ to the Slope-Intercept Form to identify the slope of the line. $\bf{\text{Solution Details:}}$ Using the properties of equality, in the Slope-Intercept Form which is given by $y=mx+b,$ the given equation is equivalent to \begin{array}{l}\require{cancel} x-5y=0 \\\\ -5y=-x \\\\ y=\dfrac{-x}{-5} \\\\ y=\dfrac{1}{5}x .\end{array} Since $m$ is the slope in the equation $y=mx+b,$ then the slope of the linear equation above is $m=\dfrac{1}{5} .$