College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 277: 55

Answer

$m=-\dfrac{11}{2}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Convert the given equation, $ 11x+2y=3 ,$ to the Slope-Intercept Form to identify the slope of the line. $\bf{\text{Solution Details:}}$ Using the properties of equality, in the Slope-Intercept Form which is given by $y=mx+b,$ the given equation is equivalent to \begin{array}{l}\require{cancel} 11x+2y=3 \\\\ 2y=-11x+3 \\\\ y=\dfrac{-11}{2}x+\dfrac{3}{2} \\\\ y=-\dfrac{11}{2}x+\dfrac{3}{2} .\end{array} Since $m$ is the slope in the equation $y=mx+b,$ then the slope of the linear equation above is $ m=-\dfrac{11}{2} .$
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