College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 277: 37

Answer

$f(k)=-2k^2+3k-6$

Work Step by Step

The function is given by: $$f(x)=-2x^2+3x-6$$ Substitute $x=k$: $$f(k)=-2(k)^2+3(k)-6$$ $$f(k)=-2k^2+3k-6$$
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