College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 275: 7

Answer

$(x+2)^2+(y-3)^2=225$

Work Step by Step

Center-radius form of equation of a circle is: $$(x-h)^2+(y-k)^2=r^2$$ Where $(h,k)$ is a center and $r$ is a radius. The given is center $(-2,3)$ and radius $r=15$. The equation becomes: $$(x-(-2))^2+(y-3)^2=15^2$$ $$(x+2)^2+(y-3)^2=225$$
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