College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 275: 3

Answer

Distance: $5$ Midpoint: $M(-6; \frac{11}{2})$

Work Step by Step

The distance between two points can be calculated by the distance formula: $d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$ $d=\sqrt{(-6-(-6))^2+(8-3)^2} \\d=\sqrt{(0+25)} \\d=\sqrt{25} \\d=5$ The midpoint can be calculated by the average of the x and y coordinates of the two points. $M(\frac{-6-6}{2};\frac{8+3}{2})= (-\frac{12}{2};\frac{11}{2})=(-6, \frac{11}{2})$
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