College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 275: 2

Answer

Distance: $\sqrt{202}$ Midpoint: $M(-\frac{5}{2};-\frac{5}{2})$

Work Step by Step

The distance between two points can be calculated by the distance formula: $d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$ $d=\sqrt{(3-(-8))^2+(-7-2)^2} \\d=\sqrt{(121+81)} \\d=\sqrt{202}$ The midpoint can be calculated by the average of the x and y coordinates of the two points. $M(\frac{-8+3}{2};\frac{-7+2}{2})= (-\frac{5}{2};-\frac{5}{2})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.