## College Algebra (11th Edition)

$x=\left\{ -11,11 \right\}$
Taking the square root of both sides, the solutions to the given equation, $x^2=121 ,$ are \begin{array}{l}\require{cancel} x=\pm\sqrt{121} \\\\ x=\pm\sqrt{(11)^2} \\\\ x=\pm11 .\end{array} Hence, the solution is $x=\left\{ -11,11 \right\} .$