College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.4 - Quadratic Equations - 1.4 Exercises - Page 112: 25


$x=\left\{ -4,4 \right\}$

Work Step by Step

Taking the square root of both sides, the solutions to the given equation, $ x^2=16 ,$ are \begin{array}{l}\require{cancel} x=\pm\sqrt{16} \\\\ x=\pm\sqrt{(4)^2} \\\\ x=\pm4 .\end{array} Hence, the solution is $ x=\left\{ -4,4 \right\} .$
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