## College Algebra (11th Edition)

$\text{Discriminant: } 0 \\\text{Number of solutions: } 1 \\\text{Type of solutions: rational solution }$
$\bf{\text{Solution Outline:}}$ To evaluate the discriminant of the given equation, $25x^2+110x+121=0 ,$ identify first the values of $a,b,$ and $c$ in the quadratic expression $ax^2+bx+c.$ Then use the Discriminant Formula. If the value of the discriminant is less than zero, then there are $\text{ 2 nonreal complex solutions .}$ If the value is $0,$ then there is $\text{ 1 distinct rational solution .}$ If the value of the discriminant is a positive perfect square, then there are $\text{ 2 rational solutions .}$ Finally, if the value of the discriminant is positive but not a perfect square, there are $\text{ 2 irrational solutions .}$ $\bf{\text{Solution Details:}}$ In the given equation above, $a= 25 ,$ $b= 110 ,$ and $c= 121 .$ Using the Discriminant Formula which is given by $b^2-4ac,$ the value of the discriminant is \begin{array}{l}\require{cancel} (110)^2-4(25)(121) \\\\= 12100-12100 \\\\= 0 .\end{array} Since the discriminant is $\text{ is equal to zero ,}$ then there is $\text{ 1 rational solutions .}$ Hence, the given equation has the following properties: \begin{array}{l}\require{cancel} \text{Discriminant: } 0 \\\text{Number of solutions: } 1 \\\text{Type of solutions: rational solution } .\end{array}