## College Algebra (11th Edition)

$x=\left\{ -\dfrac{3}{2},7 \right\}$
x^{y}$\bf{\text{Solution Outline:}}$ To solve the given equation, $-2x^2+11x=-21 ,$ express first in the form $ax^2+bx+c=0.$ Then factor the left side. Equate each factor to zero (Zero Product Property). Finally, use the properties of equality to isolate the variable in each equation. $\bf{\text{Solution Details:}}$ In the form $ax^2+bx+c=0,$ the given equation is equivalent to \begin{array}{l}\require{cancel} -2x^2+11x+21=0 \\\\ -1(-2x^2+11x+21)=-1(0) \\\\ 2x^2-11x-21=0 .\end{array} Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the factored form of equation above is \begin{array}{l}\require{cancel} (2x+3)(x-7)=0 .\end{array} Equating each factor to zero (Zero Product Property), then \begin{array}{l}\require{cancel} 2x+3=0 \\\\\text{OR}\\\\ x-7=0 .\end{array} Solving each equation results to \begin{array}{l}\require{cancel} 2x+3=0 \\\\ 2x=-3 \\\\ x=-\dfrac{3}{2} \\\\\text{OR}\\\\ x-7=0 \\\\ x=7 .\end{array} Hence, the solutions are $x=\left\{ -\dfrac{3}{2},7 \right\} .$