College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Review Exercises - Page 163: 34



Work Step by Step

Using $i^2=-1$ and the laws of exponents, the given expression $ i^{110} ,$ is equivalent to \begin{array}{l}\require{cancel} (i^{2})^{55} \\\\= (-1)^{55} \\\\= -1 .\end{array}
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