College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding: 71


$$\require{cancel} \sum_{k=1}^{40}k = 820$$

Work Step by Step

RECALL: $$\sum_{i=1}^{n}k = \dfrac{n(n+1)}{2}$$ Use the rule above to obtain: $$\require{cancel} \sum_{k=1}^{40}k = \dfrac{40(41)}{2}=820$$
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