College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding - Page 648: 70


$$\sum_{k=1}^{50}8 =400$$

Work Step by Step

RECALL: For any constant $c$, $$\sum_{i=1}^{n}c = nc$$ Use the rule above to obtain: $$\sum_{k=1}^{50}8 = 50(8) = 400$$
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