Answer
$x=60,y=30$.
Work Step by Step
Our equations according to the exercise are: $4x+2y=300, x^2+y^2=4500$.
So $y=150-2x$, thus $(150-2x)^2+x^2=4500\\22500-600x+5x^2=4500\\x^2+3600-120x=0\\(x-60)^2=0$
Thus $x=60,y=30$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 616: 87
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