College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 616: 72



Work Step by Step

Our equations according to the exercise are: $x+y=7, x^2-y^2=21$. So $x=7-y$, thus $(7-y)^2-y^2=21\\y^2-14y+49-y^2=21\\-14y+28=0\\-y+2=0\\y=2$ Thus $y=2,x=5$.
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