Answer
$y=2,x=5$
Work Step by Step
Our equations according to the exercise are: $x+y=7, x^2-y^2=21$.
So $x=7-y$, thus $(7-y)^2-y^2=21\\y^2-14y+49-y^2=21\\-14y+28=0\\-y+2=0\\y=2$
Thus $y=2,x=5$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 616: 72
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
