Answer
See below.
Work Step by Step
$x^2+y^2-2x+4y-11=0\\(x-1)^2-1+(y+2)^2-4-11=0\\(x-1)^2+(y+2)^2=16=4^2$
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence here the center is $(1,-2)$ and the radius is $4$.
Hence, using a graphing utility, the graph is:
