Answer
See below.
Work Step by Step
We know that $a^b=a^c\longrightarrow b=c$ if $a\ne1,a\ne-1$ (which applies here).
Hence here $3^x=9^{x+1}\\3^x=(3^2)^{x+1}\\3^x=3^{2(x+1)}\\x=2(x+1)\\x=2x+2\\x-2=2x\\x=-2$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Cumulative Review - Page 637: 4
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