College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 451: 132

Answer

$80$

Work Step by Step

Using the formula: we know that $70=10\log{\frac{x}{10^{-12}}}$, thus $x=10^{-5}$ is the equation for the car. For the truck the intensity is $10x=10^{-4}$, hence $L=10\log{\frac{10^{-4}}{10^{-12}}}=10\log{10^8}=10\cdot8=80$
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