College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 451: 126


See below.

Work Step by Step

Our equation is: $450=1000(1-e^{-0.15d})\\0.45=1-e^{-0.15d}\\0.55=e^{-0.15d}\\\ln{0.55}=-0.15d\\d=\ln{0.55}\frac{1}{-0.15}\approx3.99$
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