College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 451: 124


See below.

Work Step by Step

a) Our equation is: $0.5=1-e^{-0.15t}\\0.5=e^{-0.15t}\\\ln{0.5}=-0.1t\\t=\ln{0.5}\frac{1}{-0.15}\approx4.62$ b) Our equation is: $0.8=1-e^{-0.15t}\\0.2=e^{-0.15t}\\\ln{0.2}=-0.1t\\t=\ln{0.2}\frac{1}{-0.15}\approx10.73$
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