College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 450: 96



Work Step by Step

RECALL: $\ln{(x)}=y \longrightarrow e^y = x$ Use the rule above to obtain: $\ln{(e^{-2x})}=8 \longrightarrow e^8=e^{-2x}$ Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: $8=-2x$ Divide both sides by $-2$ to obtain: $\frac{8}{-2} = \frac{-2x}{-2} \\-4 = x$
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