College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 450: 102


$x =-\dfrac{\ln{(\frac{1}{3})}}{2}$

Work Step by Step

Take the natural logarithm of both sides to obtain: $\ln{e^{-2x}} = \ln{(\frac{1}{3})}$ RECALL: $\ln{e^a} = a$ Use the rule above to obtain: $-2x=\ln{(\frac{1}{3})}$ Divide by $-2$ on both sides of the equation to obtain: $x =\dfrac{\ln{(\frac{1}{3})}}{-2} \\x =-\dfrac{\ln{(\frac{1}{3})}}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.