College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding: 91

Answer

$x=\dfrac{7}{2}$

Work Step by Step

RECALL: $\log_a{x} = y \longrightarrow a^y=x$ Use the definition above to obtain: $\log_2{(2x+1)}=3 \\ \longrightarrow 2^3=2x+1 \\8=2x+1$ Subtract 1 on both sides of the equation to obtain: $\begin{array}{ccc} &8-1 &= &2x+1-1 \\&7 &= &2x\end{array}$ Divide 2 on both sides of the equation to obtain: $\frac{7}{2}=\frac{2x}{2} \\\frac{7}{2}=x$
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