## College Algebra (10th Edition)

$x=\dfrac{7}{2}$
RECALL: $\log_a{x} = y \longrightarrow a^y=x$ Use the definition above to obtain: $\log_2{(2x+1)}=3 \\ \longrightarrow 2^3=2x+1 \\8=2x+1$ Subtract 1 on both sides of the equation to obtain: $\begin{array}{ccc} &8-1 &= &2x+1-1 \\&7 &= &2x\end{array}$ Divide 2 on both sides of the equation to obtain: $\frac{7}{2}=\frac{2x}{2} \\\frac{7}{2}=x$