College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.2 - One-to-One Functions; Inverse Functions - 6.2 Assess Your Understanding - Page 422: 96

Answer

a. $18150\leq g \leq 73800$ b. $1815\leq T(g)\leq 10162.5,$ c. Domain of $g(T)$ is $1815\leq T\leq 10162.5$ and Range of $g(T)$ is $18150\leq g(T) \leq 73800$

Work Step by Step

$T(g)=1815+0.15(g-18150)$ $T(g)=1815+0.15g-2722.5,$ $T(g)=0.15g-907.5,$ a. Domain of $T(g)$ is $18150\leq g \leq 73800$ b. $T(18150)\leq T(g)\leq T(73800),$ $1815\leq T(g)\leq 10162.5,$ c. $g(T)=\frac{T+907.5}{0.15},$ Domain of $g(T)$ is $1815\leq T\leq 10162.5$ and Range of $g(T)$ is $18150\leq g(T) \leq 73800$
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