Answer
Domain is, $\{ x|x >0\}$
$f^{-1}(x)=\sqrt[4]x$
Work Step by Step
$f(x)=x^4,$
$f(x)$ is not one-to-one because the power of the function is even. Thus, the addititve inverse of an integer $x$ is gonna get the same out as the integer $x$.
Therefore, for the function to be one-to-one the domain of the function needs to be greater than or equal to $0$.
Domain is $\{ x|x >0\}$
$f(x)=x^4,$
$y=x^4,$
The inverse is,
$x=y^4,$
$\sqrt[4]x=f^{-1}(x)$
