College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.2 - One-to-One Functions; Inverse Functions - 6.2 Assess Your Understanding - Page 422: 93

Answer

a. $W(h)=77.6$ b.$h(W)=\frac{W+88}{2.3},$ c. $h(W(h))=h,$ and $W(h(W))=W,$ d.$h(80)=73.04$

Work Step by Step

$W(h)=50+2.3(h-60),$ a. $W(h)=50+2.3(72-60),$ $=50+2.3(12),$ $=77.6$ b.$h(W)=\frac{W+88}{2.3},$ c. $h(W(h))=\frac{2.3h-88+88}{2.3}=h,$ and $W(h(W))=2.3(\frac{W+88}{2.3})-88=W,$ d.$h(80)=\frac{80+88}{2.3}=73.04$
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