Answer
$f(x)=(x+1)(x-3)^2=x^3-5x^2+3x+9.$
Work Step by Step
We are given that the degree is 3, and the zeros are -1 (multiplicity 1) and 3 (multiplicity 2), hence a good function is: $f(x)=(x+1)(x-3)^2=x^3-5x^2+3x+9.$
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