Answer
$f(x)=(x+4)(x-0)(x-2)=x^3+2x^2-8x.$
Work Step by Step
We are given that the degree is 3, and the zeros are -4, 0 and 2, hence a good function is: $f(x)=(x+4)(x-0)(x-2)=x^3+2x^2-8x.$
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