Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 76

Intersection points area $(2, 5)$ and $(-4, -7)$

$f(x) = -x^2 + 9$ $g(x) = 2x + 1$ Solving $f(x) = g(x)$ $ => -x^2 + 9 = 2x + 1$ $=> x^2 + 2x - 8 = 0$ $=> (x-2)(x+4) = 0$ $=> x = -4, 2$ $f(-4) = g(-4) = -7$ $f(2) = g(2) = 5$ Intersection points area $(2, 5)$ and $(-4, -7)$