Answer
See graph
$(-1, -3)$ and $(3, 5)$
Work Step by Step
$f(x) = 2x - 1$
$g(x) = x^2 - 4$
Solving $f(x) = g(x)$
$ => x^2 -4 = 2x - 1$
$=> x^2 - 2x - 3 = 0$
$=> (x+1)(x-3) = 0$
$=> x = -1, 3$
$f(-1) = g(-1) = -3$
$f(3) = g(3) = 5$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 73
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