Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 75

Intersection points area $(-1, 3)$ and $(3, -5)$

$f(x) = -x^2 + 4$ $g(x) = -2x + 1$ Solving $f(x) = g(x)$ $ => -x^2 + 4 = -2x + 1$ $=> x^2 - 2x - 3 = 0$ $=> (x-3)(x+1) = 0$ $=> x = -1, 3$ $f(-1) = g(-1) = 3$ $f(3) = g(3) = -5$ Intersection points area $(-1, 3)$ and $(3, -5)$