Answer
(b)
Work Step by Step
We know that $y=|x|$ is symmetric about the y-axis because it has the form:
$f(x)=\left\{\begin{array}{ll}
-x & x\lt0 \\
x & x\gt0
\end{array}\right.$
That is, the graph is that of a line with slope -1 until $x=0$, followed by a line with slope $1$ after $x=0$ and both lines have the same $y-intercept$ of $0$. Hence, the graph is symmetrical.
