Answer
True
Work Step by Step
The cube function, $f(x)=x^3$, is odd because:
$f(-x)=(-x)^3=-(x^3)=-f(x)$
It is increasing on the interval $(-\infty,\infty)$ -- in other words, for all values of $x$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 3 - Section 3.4 - Library of Functions; Piecewise-defined Function - 3.4 Assess Your Understanding - Page 244: 6
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