## College Algebra (10th Edition)

y-intercept: $(0,-8)$ x-intercept: $(2,\ 0)$
To find the $y$ intercepts, we set $x=0$: $y=0^{3}-8$ $y=-8$ To find the $x$ intercepts, we set $y=0$: $0=x^3-8$ $x^3=8$ $x=2$