## College Algebra (10th Edition)

$x=\frac{1}{2}$
We solve: $\sqrt{2x+3}=2$ We square both sides: $(\sqrt{2x+3})^{2}=2^{2}$ And solve for $x$: $2x+3=4$ $2x=4-3$ $2x=1$ $x=\frac{1}{2}$