College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Cumulative Review - Page 271: 6



Work Step by Step

We solve: $\sqrt{2x+3}=2$ We square both sides: $(\sqrt{2x+3})^{2}=2^{2}$ And solve for $x$: $2x+3=4$ $2x=4-3$ $2x=1$ $x=\frac{1}{2}$
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